2 solutions

  • 2
    @ 2024-12-26 13:14:19
    #include<bits/stdc++.h>
    using namespace std;
    const int N=15;
    int g[N][N];
    int main()
    {
    	int n,d;
    	cin>>n>>d;
    	for(int i=1;i<=n;i++)
    	{
    		for(int j=1;j<=d;j++)
    		{
    			cin>>g[i][j];
    		}
    	}
    	int res=0;
    	for(int i=1;i<=n;i++) //第一个点 
    	{
    		for(int j=i+1;j<=n;j++) //第二个点 
    		{
    			int sum=0; //计算和 
    			for(int k=1;k<=d;k++)  
    			{
    				sum+=(g[i][k]-g[j][k])*(g[i][k]-g[j][k]);	
    			}
    			int k=sqrt(sum);
    			if(k*k==sum) //判断开方以后是否是完全平方数 
    			{
    				res++;
    			}
    		}
    	}
    	cout<<res;
    	return 0;
    }
    
    • -2
      @ 2024-12-29 16:14:43
      我是奶龙
    • 1

    Information

    ID
    2136
    Time
    2000ms
    Memory
    1024MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    42
    Accepted
    13
    Uploaded By