2 solutions
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-1
#include<bits/stdc++.h> using namespace std; const int N=1000010; int a[N],b[N]; int main() { int n; cin>>n; for(int i=1;i<=n;i++) { cin>>a[i]; b[a[i]]++;//a[i]出现的次数增加一次 } int maxv=1; for(int i=0;i<=1000;i++) { if(b[i]>b[maxv])//b[i]的值就是i出现的次数 { maxv=i; } } cout<<maxv; return 0; }
- 1
Information
- ID
- 2870
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 3
- Tags
- # Submissions
- 10
- Accepted
- 4
- Uploaded By