2 solutions

  • 0
    @ 7 months ago
    #include<bits/stdc++.h>
    using namespace std;
    bool check(int x) //判断是否含有7 
    {
    	while(x)
    	{
    		int ge=x%10;
    		if(ge==7) return true;
    		x/=10;
    	}
    	return false;
    }
    bool check2(int x) //判断是否是回文 
    {
    	int t=x;
    	int res=0;
    	while(t)
    	{
    		int ge=t%10;
    		res=res*10+ge;
    		t/=10;
    	}
    	if(x==res) return true;
    	return false;
    }
    int main()
    {
    	int n,m;
    	cin>>n>>m;
    	int cnt=0;
    	for(int i=n;i<=m;i++)
    	{
    		if(check(i)&&check2(i)) //同时含有7和回文 
    		{
    			cnt++;
    		}
    	}
    	cout<<cnt;
    	return 0;
    }
    
    • -1
      @ 7 months ago
      #include<bits/stdc++.h>
      using namespace std;
      bool check(int x) //判断是否含有7 
      {
      	while(x)
      	{
      		int ge=x%10;
      		if(ge==7) return true;
      		x/=10;
      	}
      	return false;
      }
      bool check2(int x) //判断是否是回文 
      {
      	int t=x;
      	int res=0;
      	while(t)
      	{
      		int ge=t%10;
      		res=res*10+ge;
      		t/=10;
      	}
      	if(x==res) return true;
      	return false;
      }
      int main()
      {
      	int n,m;
      	cin>>n>>m;
      	int cnt=0;
      	for(int i=n;i<=m;i++)
      	{
      		if(check(i)&&check2(i)) //同时含有7和回文 
      		{
      			cnt++;
      		}
      	}
      	cout<<cnt;
      	return 0;
      }
      
      
      • 1

      Information

      ID
      1271
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      3
      Tags
      # Submissions
      42
      Accepted
      12
      Uploaded By