排序$(Onlg^n)$

#include<bits/stdc++.h>
using namespace std;
const int N=310;
struct Stu{
    int total,yuwen,shuxue,yingyu,id;
};
Stu s[N];
bool cmp(Stu a,Stu b)
{
    if(a.total>b.total) return 1; //总分 
    if(a.total==b.total&&a.yuwen>b.yuwen) return 1; //总分相同语文 
    if(a.total==b.total&&a.yuwen==b.yuwen&&a.id<b.id) return 1; //总分语文相同，学号 
    return 0; //不符合当前规则 
}
int main()
{
    int n;
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>s[i].yuwen>>s[i].shuxue>>s[i].yingyu;
        s[i].total=s[i].yingyu+s[i].yuwen+s[i].shuxue;
        s[i].id=i;
    }
    sort(s+1,s+1+n,cmp);
    for(int i=1;i<=5;i++)
    {
        cout<<s[i].id<<" "<<s[i].total<<endl;
    }
}