1 solutions

  • 0
    @ 2025-4-8 16:29:37
    #include<bits/stdc++.h>
    using namespace std;
    const int N=2e5+10;
    int p[N],q[N]; 
    int main()
    {
    	int n;
    	cin>>n;
    	for(int i=1;i<=n;i++)
    	{
    		int x;
    		cin>>x;
    		q[x]=i; //x在原始序列中出现的位置是i 
    	}
    	for(int i=1;i<=n;i++)
    	{
    		cout<<q[i]<<" "; //输出每个数在原始序列中出现的位置 
    	}
    	return 0;
    }
    
    
    • 1

    Information

    ID
    2373
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    # Submissions
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