1 solutions
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0
#include<bits/stdc++.h> using namespace std; string dfs(int x) { string res; for(int i=20;i>=0;i--) { if(x>>i&1) //2^i次方存在 { if(res.size()) res+='+'; if(!i) res+="2(0)"; else if(i==1) res+="2"; else res+="2("+dfs(i)+")"; } } return res; } int main() { int n; cin>>n; cout<<dfs(n); return 0; }
- 1
Information
- ID
- 239
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 5
- Tags
- # Submissions
- 16
- Accepted
- 9
- Uploaded By