1 solutions

  • 0
    @ 2024-10-24 13:21:50
    #include<bits/stdc++.h>
    using namespace std;
    const int N=20010;
    int f[N]; //f[i][j]表示前i个物品,背包体积为j的时候可以凑出来的空间 
    int main()
    {
    	int V,n;
    	cin>>V>>n;
    	for(int i=1;i<=n;i++)
    	{
    		int v;
    		cin>>v;
    		for(int j=V;j>=v;j--)
    		{
    			f[j]=max(f[j],f[j-v]+v);
    		}
    	}
    	cout<<V-f[V];
    	return 0;
    }
    
    • 1

    Information

    ID
    987
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    5
    Tags
    (None)
    # Submissions
    45
    Accepted
    12
    Uploaded By