1 solutions

  • 1
    @ 2024-4-13 14:04:33
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e5+10;
    int a[N];
    set<int> h;
    int main()
    {
    	int n;
    	cin>>n;
    	for(int i=1;i<=n;i++)
    		cin>>a[i];
    	int x;
    	cin>>x;
    	int cnt=0;
    	for(int i=1;i<=n;i++){
    		if(h.count(x-a[i])) //统计之前的差值有没有出现过 
    			cnt++;
    		h.insert(a[i]); //插入当前值 
    	}
    	cout<<cnt;
    	return 0;
    }
    
    • 1

    Information

    ID
    159
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    20
    Accepted
    8
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