2 solutions

  • 0
    @ 2024-11-30 15:14:58
    #include<bits/stdc++.h>
    using namespace std;
    int a[100001];
    int main()
    {
    	int num=0,j=0,sum=1;
    	cin>>num>>j;
    	while(num!=0){
    		a[sum]=num%j;
    		num=(num-a[sum])/j;
    		sum++;
    	}
    	for(int i=sum-1;i>=1;i--){
    		cout<<a[i];
    	}
    	return 0;
    }
    
    
    • 0
      @ 2024-4-21 15:41:53
      #include<bits/stdc++.h>
      using namespace std;
      int a[100001];
      int main()
      {
      	int num=0,j=0,sum=1;
      	cin>>num>>j;
      	while(num!=0){
      		a[sum]=num%j;
      		num=(num-a[sum])/j;
      		sum++;
      	}
      	for(int i=sum-1;i>=1;i--){
      		cout<<a[i];
      	}
      	return 0;
      }
      
      • 1

      Information

      ID
      153
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      3
      Tags
      (None)
      # Submissions
      21
      Accepted
      14
      Uploaded By