1 solutions
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0
#include<bits/stdc++.h> using namespace std; const int N=25; int a[N],b[N],c[N]; int main() { string s; cin>>s; int n=s.size(); for(int i=0,j=n-1;i<n;i++,j--) { a[i]=s[j]-'0'; b[i]=2*a[i]; } for(int i=0;i<n;i++) { b[i+1]+=b[i]/10; b[i]%=10; } memcpy(c,b,sizeof a);//c=b; sort(a,a+n); sort(b,b+n); //统计a和b对应位置不同的数的个数 int cnt=0; for(int i=0;i<n;i++) { if(a[i]!=b[i]) cnt++; } if(!cnt) cout<<"Yes"<<endl; else cout<<"No"<<endl; for(int i=n-1;i>=0;i--) { cout<<c[i]; } return 0; }
- 1
Information
- ID
- 147
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 9
- Accepted
- 3
- Uploaded By