2 solutions
-
4
#include<bits/stdc++.h> using namespace std; const int N=1e6+10; int a[N]; int n,m; bool check(int x) { long long res=0; //总合 for(int i=1;i<=n;i++) { res=res+max(0,a[i]-x); } return res>=m; //当前长度是否可以符合要求 } int main() { cin>>n>>m; int l=0,r=0; for(int i=1;i<=n;i++) { cin>>a[i]; r=max(r,a[i]); } while(l<r) { int mid=l+r+1>>1; if(check(mid)) l=mid; else r=mid-1; } cout<<l; return 0; }
-
-2
- 无注释版本
#include<bits/stdc++.h> using namespace std; const int N=1e6+10; int a[N]; int n,m; bool check(int x) { long long res=0; for(int i=1;i<=n;i++) { res=res+max(0,a[i]-x); } return res>=m; } int main() { cin>>n>>m; int l=0,r=0; for(int i=1;i<=n;i++) { cin>>a[i]; r=max(r,a[i]); } while(l<r) { int mid=l+r+1>>1; if(check(mid)) l=mid; else r=mid-1; } cout<<l; return 0; }
- 1
Information
- ID
- 952
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 70
- Accepted
- 26
- Uploaded By