1 solutions

  • 0
    @ 2025-4-26 13:58:11
    #include<bits/stdc++.h>
    using namespace std;
    const int N=60;
    int a[N];
    int main()
    {
    	int x,p;
    	cin>>x>>p;
    	int idx=0;//起始下标 
    	while(x)  //短除法 
    	{
    		a[idx++]=x%p;
    		x/=p;
    	}
    	reverse(a,a+idx); //翻转 
    	for(int i=0;i<idx;i++)
    	{
    		if(a[i]>=10) //将大于等于10的数字转成对应的字母 
    		{
    			char c=a[i]-10+'A';
    			cout<<c;
    		}
    		else
    		{
    			cout<<a[i];
    		}
    	} 
    	return 0;
    }
    
    • 1

    Information

    ID
    1195
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    24
    Accepted
    4
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