1 solutions
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0
#include<bits/stdc++.h> using namespace std; const int N=110; char a[N][N],b[N][N]; int main() { int n; cin>>n; for(int i=1;i<=n;i++) //输入第一个二维字符数组 { for(int j=1;j<=n;j++) { cin>>a[i][j]; } } for(int i=1;i<=n;i++) //输入第二个二维字符数组 { for(int j=1;j<=n;j++) { cin>>b[i][j]; } } for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++) { if(a[i][j]!=b[i][j]) //找到不同的位置并输出 { cout<<i<<" "<<j<<endl; } } } return 0; }
- 1
Information
- ID
- 2454
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 10
- Accepted
- 6
- Uploaded By