2 solutions

  • 0
    @ 2025-3-17 17:59:47
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e2+10;
    char c[N];
    int main()
    {
        cin.getline(c,N);
        int n=strlen(c);
        for(int i=0;i<=n;i++)
        {
            if(c[i]>='a'&&c[i]<='z')
            {
                c[i]=c[i]-'a'+'A';
            }
        }
        cout<<c;
        return 0;
    }
    
  • -1
    @ 2024-10-5 11:49:48

    这是题解

    • 1

    【例】将字符串中的小写字母转换成大写字母

    Information

    ID
    915
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    70
    Accepted
    34
    Uploaded By