5 solutions

  • 1
    @ 2025-1-20 10:24:55
    #include<bits/stdc++.h>
    using namespace std;
    const int N=600;
    char s1[N],s2[N];
    int main()
    {
        double m,n;
        cin>>m;
        cin>>s1>>s2;
        double l=strlen(s1);
        for(int i=0;i<l;i++)
        {
            if(s1[i]==s2[i])
            {
                n+=1;
            }
        }
        double c=n/l;
        if(c>=m)
        {
            cout<<"yes";
        }
        else
        {
            cout<<"no";
        }
        return 0;
    }
    
    
    • 1
      @ 2024-11-9 15:02:26
      #include<bits/stdc++.h>
      using namespace std;
      const int N=600;
      char s1[N],s2[N];
      int main()
      {
      	double m,n;
      	cin>>m;
      	cin>>s1>>s2;
      	double l=strlen(s1);
      	for(int i=0;i<l;i++)
      	{
      		if(s1[i]==s2[i])
      		{
      			n+=1;
      		}
      	}
      	double c=n/l;
      	if(c>=m)
      	{
      		cout<<"yes";
      	}
      	else
      	{
      		cout<<"no";
      	}
      	return 0;
      }
      
      • 1
        @ 2024-7-12 14:36:35
        #include<bits/stdc++.h>
        using namespace std;
        const int N=600;
        char s1[N],s2[N];
        int main()
        {
            double m,n;
            cin>>m;
            cin>>s1>>s2;
            double l=strlen(s1);
            for(int i=0;i<l;i++)
            {
                if(s1[i]==s2[i])
                {
                    n+=1;
                }
            }
            double c=n/l;
            if(c>=m)
            {
                cout<<"yes";
            }
            else
            {
                cout<<"no";
            }
            return 0;
        }
        
        • 0
          @ 2025-3-17 18:15:41
          #include<bits/stdc++.h>
          using namespace std;
          const int N=1e2*5+10;
          char a[N],b[N];
          int main()
          {
              int res=0;
              double y;
              cin>>y>>a>>b;
              int x;
              x=strlen(a);
              for(int i=0;i<x;i++)
              {
                  if(a[i]==b[i])
                  {
                      res++;
                  }
              }
              double n;
              n=res*1.0/x;
              if(n>y)
              {
                  cout<<"yes";
              }
              else if(n<y)
              {
                  cout<<"no";
              }
              else
              {
                  cout<<"yes";
              }
              return 0;
          }
          
        • -2
          @ 2024-11-2 15:57:18
          
           jike1994 LV 1 SU @ 3 个月前 
          #include<bits/stdc++.h>
          using namespace std;
          const int N=600;
          char s1[N],s2[N];
          int main()
          {
              double m,n;
              cin>>m;
              cin>>s1>>s2;
              double l=strlen(s1);
              for(int i=0;i<l;i++)
              {
                  if(s1[i]==s2[i])
                  {
                      n+=1;
                  }
              }
              double c=n/l;
              if(c>=m)
              {
                  cout<<"yes";
              }
              else
              {
                  cout<<"no";
              }
              return 0;
          }
          
          • 1

          Information

          ID
          914
          Time
          1000ms
          Memory
          256MiB
          Difficulty
          1
          Tags
          (None)
          # Submissions
          71
          Accepted
          33
          Uploaded By