2 solutions

  • 3
    @ 2024-7-13 11:38:43
    #include<bits/stdc++.h>
    using namespace std;
    const int N=100,M=100;
    int a[N][M];
    int main()
    {
    	int n,m,s=0;
    	cin>>n>>m;
    	for (int i=1;i<=n;i++)
    	{
    		for (int j=1;j<=m;j++)
    		{
    			cin>>a[i][j];
    		}
    	}
    	for (int i=1;i<=n;i++)
    	{
    		for (int j=1;j<=m;j++)
    		{
    			if (i==1 || i==n||j==1 || j==m)
    			{
    				s+=a[i][j];
    			}
    				
    		}
    	}
    	cout<<s;
    	return 0;
    }
    
    • @ 2024-7-13 11:40:42

      太有实力了

    • @ 2024-7-13 11:41:03

      必须支持

  • 0
    @ 2025-3-13 20:25:08
    
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e2+10;
    int a[N][N];
    int main()
    {
        int n,m,cnt;
        cin>>n>>m;
        cnt=0;
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
                cin>>a[i][j];
            }
        }
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
                if(i==1
    • 1

    Information

    ID
    904
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    89
    Accepted
    38
    Uploaded By