2 solutions
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3
#include<bits/stdc++.h> using namespace std; const int N=100,M=100; int a[N][M]; int main() { int n,m,s=0; cin>>n>>m; for (int i=1;i<=n;i++) { for (int j=1;j<=m;j++) { cin>>a[i][j]; } } for (int i=1;i<=n;i++) { for (int j=1;j<=m;j++) { if (i==1 || i==n||j==1 || j==m) { s+=a[i][j]; } } } cout<<s; return 0; }
- 1
Information
- ID
- 904
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 89
- Accepted
- 38
- Uploaded By