3 solutions

  • 2
    @ 2024-12-20 10:46:07
    #include<bits/stdc++.h>
    using namespace std;
    const int N=100;
    long long f[N]={0,1,2};//f[i]表示长度为i的长方形的方案数目 
    int main()
    {
    	int n;
    	cin>>n;
    	for(int i=3;i<=n;i++)
    	{
    		f[i]=f[i-1]+f[i-2];
    		//   竖着   横着 
    	}
    	cout<<f[n];
    	return 0;
    }
    
    • 2
      @ 2024-3-24 10:06:34
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
          long long a,b,c;
          c=1,a=1,b=1;
          int n;
          cin>>n;
          for(int i =3;i<=n+1;i++)
          {
              c=a+b;
              a=b;
              b=c;
          }
          cout<<c;
          return 0;
      }
      //😅😅😅😅😅😅😅😅😅
      
      • 1
        @ 2025-1-20 9:21:16
        #include<bits/stdc++.h>
        using namespace std;
        const int N=100;
        long long f[N]={0,1,2};//f[i]表示长度为i的长方形的方案数目 
        int main()
        {
        	int n;
        	cin>>n;
        	for(int i=3;i<=n;i++)
        	{
        		f[i]=f[i-1]+f[i-2];
        		//   竖着   横着 
        	}
        	cout<<f[n];
        	return 0;
        }
        
        
        • 1

        Information

        ID
        1257
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        1
        Tags
        (None)
        # Submissions
        69
        Accepted
        31
        Uploaded By