5 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=10010; int a[N]; int main() { int L,m; cin>>L>>m; for(int i=1;i<=m;i++) //枚举区间个数 { int l,r; cin>>l>>r; for(int j=l;j<=r;j++) //标记区间l到r之间的所有数 { a[j]=1; } } int c=0; for(int i=0;i<=L;i++) //判断整个区间的每个位置 { if(a[i]==0) { c++; } } cout<<c; return 0; }
- 1
Information
- ID
- 895
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 141
- Accepted
- 47
- Uploaded By