2 solutions

  • 1
    @ 2025-6-14 10:44:22

    #include<bits/stdc++.h> using namespace std; int main() { int a,b,c,k=0; cin>>a>>b; for(int i=1;i<=b;i++) { cin>>c; //当前取到的药的数量 if(c<=a) //可以取 { a=a-c; } else //取不到 { k=k+1; }

    }
    cout<<k;
    return 0;
    

    }

    • 1
      @ 2024-5-24 11:18:12
      #include<bits/stdc++.h>
      using namespace std;
      int main() 
      {
      	int a,b,c,k=0;
      	cin>>a>>b;
      	for(int i=1;i<=b;i++)
      	{
      		cin>>c; //当前取到的药的数量 
      		if(c<=a) //可以取 
      		{
      			a=a-c;
      		}
      		else //取不到 
      		{
      			k=k+1;	
      		}
      		
      	}
      	cout<<k;
      	return 0;
      }
      
      • 1

      Information

      ID
      880
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      124
      Accepted
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