4 solutions

  • 1
    @ 2025-1-13 10:22:51

    #include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; if(n<100&&n>1) { cout <<"yes"; } return 0; }

    • 0
      @ 2025-4-12 11:38:01

      #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

      • 0
        @ 2024-12-17 20:36:35
        #include<bits/stdc++.h>
        using namespace std;
        int main()
        {
        	int a;
        	cin>>a;
        	if(a<100&&a>1)
        	{
        		cout<<"yes";
        	}
        	else
        	{
        		cout<<"";
        	}
        	return 0;
        }
        
        • -2
          @ 2024-11-30 10:38:44

          pj23jr23je023jr023re0923i23iur0923r0923ur0pr

          • 1

          Information

          ID
          22
          Time
          1000ms
          Memory
          256MiB
          Difficulty
          1
          Tags
          (None)
          # Submissions
          158
          Accepted
          62
          Uploaded By