2 solutions

  • 1
    @ 2024-7-17 19:00:36
    #include <bits/stdc++.h>
    using namespace std;
    int main ()
    {
        int n;
        cin>>n;
        if (n%3==0 && n%5==0)
        {
            cout<<"YES";
        }
        else
        {
            cout<<"NO";
        }
        return 0;
    }
    
    • 0
      @ 2025-4-12 11:36:48

      #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

      • 1

      Information

      ID
      859
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      163
      Accepted
      69
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