2 solutions

  • 0
    @ 2024-4-21 15:41:53
    #include<bits/stdc++.h>
    using namespace std;
    int a[100001];
    int main()
    {
    	int num=0,j=0,sum=1;
    	cin>>num>>j;
    	while(num!=0){
    		a[sum]=num%j;
    		num=(num-a[sum])/j;
    		sum++;
    	}
    	for(int i=sum-1;i>=1;i--){
    		cout<<a[i];
    	}
    	return 0;
    }
    

    Information

    ID
    153
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    21
    Accepted
    14
    Uploaded By