5 solutions

  • -2
    @ 2024-11-16 9:40:36
    #include<bits/stdc++.h>
    using namespace std;
    const int N=310;
    double a[N];
    int main()
    {
    	int n;
    	cin>>n;
    	int maxid,minid;
    	double sum=0;
    	for (int i=1;i<=n;i++)
    	{
    		cin>>a[i];
    		if (i==1 || a[i]>a[maxid])
    		{
    			maxid=i;
    		}
    		if (i==1 || a[i]<a[minid])
    		{
    			minid=i;
    		}
    		sum+=a[i];
    	}
    	sum=sum-a[maxid]-a[minid];
    	double ave=sum/(n-2);
    	double res=0;
    	for (int i=1;i<=n;i++)//
    	{
    		if (i==maxid || i==minid) continue; 
    		double t=abs(a[i]-ave);
    		if (t>res)
    		{
    			res=t;
    		}
    	}
    	cout<<fixed<<setprecision(2)<<ave<<" "<<res; 
    	return 0;
    }
    

    Information

    ID
    897
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    229
    Accepted
    40
    Uploaded By