6 solutions

  • -2
    @ 2024-10-20 11:27:32
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	int maxv=0,h=0;
    	//maxv表示当前已有的连续正常血压的最长小时数,h表示以第i个小时结尾的连续正常血压小时数目
    	for(int i=1;i<=n;i++)
    	{
    		int a,b;
    		cin>>a>>b;
    		if(a>=90&&a<=140&&b>=60&&b<=90)
    		{
    			h++;	
    		}	
    		else
    		{
    			h=0;
    		}
    		if(h>maxv) //以第i个小时结尾的连续正常血压数已经高于已有最大值 
    		{
    			maxv=h;
    		}
    	} 
    	cout<<maxv;
    	return 0;
    }
    
    

    Information

    ID
    881
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    179
    Accepted
    51
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