7 solutions
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-1
#include<bits/stdc++.h> using namespace std; const int N=20; int g[20][20]; int main() { int n; cin>>n; int cnt=1; for(int i=1;i<=n;i++) //填写第i列的起点 { for(int x=1,y=i;x<=i;x++,y--) //从(1,i) { g[x][y]=cnt++; } } for(int i=1;i<=n;i++) { for(int j=1;j<=n-i+1;j++) { if(g[i][j] !=0) cout<<g[i][j]<<" "; } cout<<endl; } return 0; }
Information
- ID
- 82
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 4
- Tags
- (None)
- # Submissions
- 81
- Accepted
- 29
- Uploaded By