9 solutions
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-2
#include<bits/stdc++.h> using namespace std; int main() { int n,a[3001],b[3000]; cin>>n; for(int i=1;i<=n;i++) { cin>>a[i]; } bool jud; if(n==1) cout<<"Not jolly"; else { for(int j=1;j<=n-1;j++) { b[j]=abs(a[j+1]-a[j]); } for(int k=1;k<=n-2;k++) { if(b[k+1]-b[k]==1) jud=true; else { jud=false; break; } } if(jud) cout<<"Jolly"; else cout<<"Not jolly"; } }
Information
- ID
- 75
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 143
- Accepted
- 47
- Uploaded By