7 solutions
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-3
#include<bits/stdc++.h> using namespace std; const int N=110; double a[N][N]; int main() { int n; cin>>n; int m=0; double s=0; for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++) { cin>>a[i][j]; } } for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++) { if(j>i) { s+=a[i][j]; m++; } } } cout<<fixed<<setprecision(1)<<s/m; return 0; }
Information
- ID
- 70
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 137
- Accepted
- 39
- Uploaded By