7 solutions

  • -1
    @ 2024-10-27 11:09:17
    using namespace std;
    int main()
    {
        int n;
        cin>>n;
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=n-i;j++) //空格的数目
            {
                cout<<" ";
            }
            for(int j=1;j<i*2;j++)//*的数目
            {
                cout<<"*";
            }
            cout<<endl;
        }
        return 0;
    }
    
    
    
    

    Information

    ID
    68
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    90
    Accepted
    44
    Uploaded By