14 solutions

  • -2
    @ 2025-1-4 11:16:20
    #include<bits/stdc+.+h>
    using namespace std;
    int main(){
    	int n;
    	cin>>n;
    	n=n/21;
    	for(int i=1;i<=n;i++) //枚举倒三角的i行 
    	{
    		//1.先输出空格
    		for(int j=1;j<i;j++)
    		{
    			cout<<" ";
    		}
    		for(int j=2*n+1-2*i;j>=1;j--)
    		{
    			cout<<"*";	
    		} 
    		cout<<endl;
    	}
    	for(int i=2;i<=n;i++)
    	{
    		for(int j=1;j<=n-i;j++)
    		{
    			cout<<" ";
    		}
    		for(int j=1;j<=2*i-1;j++)
    		{
    			cout<<"*";
    		}
    		cout<<endl;
    	}
    	return 0;
    }
    
    

    Information

    ID
    67
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    87
    Accepted
    48
    Uploaded By