6 solutions
-
-1
#include<bits/stdc++.h> using namespace std; int main(){ int n; cin >> n; for(int i = 1;i<=2*n-1;i++){ if(i == 1||i == 2*n -1){ for(int j =1; j<=3*n-2;j++){ if(j>=n&&j<2*n){ cout << "*"; } else cout << " "; } }else{ for(int k = 0;k<3*n-2;k++){ if(k == abs(n-i) || k == 2*n -1 + (i-2)||k == (n-i)+(3*n-3)){ cout << "*"; }else{ cout << " "; } //下边 } } cout << endl; } return 0;
Information
- ID
- 66
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 73
- Accepted
- 35
- Uploaded By