5 solutions
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-1
#include<bits/stdc++.h> using namespace std; int a[30][30]; int main() { int n; cin>>n; for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { cin>>a[i][j]; } } int x=0,y=0; for(int i=1;i<=n;i++) { a[x][y]+=10; x++; y++; } y=n-1,x=0; for(int i=1;i<=n;i++) { a[x][y]+=10; y--; x++; } if(n%2!=0) { a[(n+1)/2-1][(n+1)/2-1]-=10; } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { cout<<a[i][j]<<" "; } cout<<endl; } return 0; }
Information
- ID
- 64
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 83
- Accepted
- 35
- Uploaded By