9 solutions
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-2
using namespace std; const int N=25; int a[N]; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i];//输入 } for(int i=1;i<=n;i++){ for(int j=1;j+1<=n-i+1;j++){//依此比较位置 if(a[j]>a[j+1]){//判断大小 int t=a[j]; a[j]=a[j+1];//换位置 a[j+1]=t;//换位置 } } } for(int i=1;i<=n;i++){//输出 cout<<a[i]<<" ";//间隔 } return 0; }
Information
- ID
- 60
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 162
- Accepted
- 49
- Uploaded By