9 solutions

  • -2
    @ 2024-11-17 9:40:18
    using namespace std;
    const int N=25;
    int a[N];
    int main(){
    	int n;
    	cin>>n;
    	for(int i=1;i<=n;i++){
    		cin>>a[i];//输入 
    	}
    	for(int i=1;i<=n;i++){
    		for(int j=1;j+1<=n-i+1;j++){//依此比较位置 
    			if(a[j]>a[j+1]){//判断大小 
    				int t=a[j];
    				a[j]=a[j+1];//换位置 
    				a[j+1]=t;//换位置 
    			}
    		}
    	}
    	for(int i=1;i<=n;i++){//输出 
    		cout<<a[i]<<" ";//间隔 
    	}
    	return 0;
    }
     
    
    

    Information

    ID
    60
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    162
    Accepted
    49
    Uploaded By