7 solutions

  • -1
    @ 2025-3-1 10:47:37
    #include<bits/stdc++.h>
    using namespace std;
    const int N=10010;
    bool  f[N][N];
    //f[i][j]=1 表示i到j这段是回文串 
    int main()
    {
    	string s;
    	cin>>s;
    	int n=s.size();
    	s=" "+s;
    	for(int i=1;i<=n;i++) f[i][i]=1; //一个字符一定是回文 
    	int ans=n;
    	for(int i=n;i>=1;i--)
    	{
    		for(int j=i+1;j<=n;j++)
    		{
    			if(s[i]!=s[j]) continue;//一定不符合要求 
    			if(j==i+1||f[i+1][j-1])
    			{
    				ans++;
    				f[i][j]=true;
    			}
    		}
    	}
    	cout<<ans;
    	return 0;
    }

    Information

    ID
    208
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    # Submissions
    44
    Accepted
    10
    Uploaded By