1 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=2010,P=1e9+7; int c[N][N]; int main() { int n; cin>>n; for(int i=0;i<N;i++) { for(int j=1;j<=i;j++) { if(j==0) c[i][j]=1; c[i][j]=(c[i-1][j-1],c[i-1][j])%P } } while(n--) { int a,b; cin>>a>>b; cout<<c[a][b]<<endl; } return 0; }
Information
- ID
- 192
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 42
- Accepted
- 13
- Uploaded By